Question

Si tanα = 2/3 y α agudo, calcula: L = 4csc2α – 3

Answer 1

Explicación paso a paso:

C

a=2 b=raiz13

B @ A

c=3

tg@= 2/3 = c.o/c.a

pitagoras

${h}^{2} = {2}^{2} + {3}^{2}$

${h}^{2} = 4 + 9$

${h}^{2} = 13$

$h = \sqrt{13}$

L = 4csc2@-3

L= 4.2(h/o)-3

$l = 4.2( \frac{ \sqrt{13} }{2} ) - 3$

$l = 4 \times \sqrt{13} - 3$

l=11.42