Question

la última
$\tan(x) + \cot(x) = \frac{1}{ \sin(x) \cos(x) }$
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Answer 1

Recuerda:

$\sin {}^{2} (x) + \cos {}^{2} (x) = 1$

$\tan(x) = \frac{ \sin(x) }{ \cos(x) }$

$\cot(x) = \frac{ \cos(x) }{ \sin(x) }$

...

$\frac{ \sin(x) }{ \cos(x) } + \frac{ \cos(x) }{ \sin(x) } = \frac{1}{ \sin(x) \cos(x) }$

$\frac{ \sin(x) \sin(x) }{ \sin(x) \cos(x) } + \frac{ \cos(x) \cos(x) }{ \sin(x) \cos(x) } = \frac{1}{ \sin(x) \cos(x) }$

$\frac{ \sin {}^{2} (x) + \cos {}^{2} (x) }{ \sin(x) \cos(x) } = \frac{1}{ \sin(x) \cos(x) }$

$\frac{1}{ \sin(x) \cos(x) } = \frac{1}{ \sin(x) \cos(x) }$

$1 = 1$

La igualdad es verdadera