Question

log√x+1 = log(x - 2) − log√x + 2

Answer 1

Explicación paso a paso:

log (x+1)½= log(x-2) – log(x+2)½

½ log x+1 = log x-2 – ½ log x+2 /×2

log x+1 = log (x-2)² – log x+2

(x-2)²

log x+1 =log ( ‐-------)

x+2

x+1 = (x-2)² / x+2

(x+1)×(x+2)= (x-2)²

x²+3x+2=x²-4x+4

3x+4x=4-2

7x=2

x=7/2.