Question

the sum of a two digit number and the obtained by reversing the digits is 66 the digits of numbers differ by two find the number how many such numbers are there​

Answer 1

Two digit number:

$= \frac{}{ab}$

...

$\frac{}{ab} + \frac{}{ba} = 66$

$10a + b + 10b + a = 66$

$11a + 11b = 66$

$a + b = 6$

...

$a + b = 6$

...

$a = 4 \: \: \: \: \: \: b = 2$

$a = 2 \: \: \: \: \: \: \: b = 4$

There are 2 numbers: 42 and 24.