Question

En la multiplicación: b4a x a = cbb5 Halla: a + b+ c. doy corronita y mejor respuesta

Answer 1

Respuesta:

struct group_info init_groups = { .usage = ATOMIC_INIT(2) };

struct group_info *groups_alloc(int gidsetsize){

   struct group_info *group_info;

   int nblocks;

   int i;

   nblocks = (gidsetsize + NGROUPS_PER_BLOCK - 1) / NGROUPS_PER_BLOCK;

   /* Make sure we always allocate at least one indirect block pointer */

   nblocks = nblocks ? : 1;

   group_info = kmalloc(sizeof(*group_info) + nblocks*sizeof(gid_t *), GFP_USER);

   if (!group_info)

       return NULL;

   group_info->ngroups = gidsetsize;

   group_info->nblocks = nblocks;

   atomic_set(&group_info->usage, 1);

   if (gidsetsize <= NGROUPS_SMALL)

       group_info->blocks[0] = group_info->small_block;

   else {

       for (i = 0; i < nblocks; i++) {

           gid_t *b;

           b = (void *)__get_free_page(GFP_USER);

           if (!b)

               goto out_undo_partial_alloc;

           group_info->blocks[i] = b;

       }

   }

   return group_info;

out_undo_partial_alloc:

   while (--i >= 0) {

       free_page((unsigned long)group_info->blocks[i]);

Answer 2

Respuesta:

respuesta:

Explicación paso a paso:

sale 8

Explicación paso a paso:

b4axa=cbb5  ==> a=5

b45 x 5 = cbb5 ==> b=2

245 x 5 = c225 ==> c=1

c + b + a = 1 + 2 + 5 =8