Question

Me pueden ayudar con esto porfa

Answer 1

Recuerda:

${x}^{ \frac{1}{y} } = \sqrt[y]{x}$

${x}^{ - y} = \frac{1}{ {x}^{y} }$

...

a)

$= \frac{ \sqrt{25} + \frac{1}{ \sqrt[3]{64} } }{ \sqrt[5]{32} } \\ = \frac{ \sqrt{ {5}^{2} } + \frac{1}{ \sqrt[3]{ {4}^{3} } } }{ \sqrt[5]{ {2}^{5} } } \\ = \frac{5 + \frac{1}{4} }{2} \\ = \frac{ \frac{21}{4} }{2} \\ = \frac{21}{8}$

b)

$= \frac{ \sqrt[3]{125} + \sqrt{36} }{ \sqrt{100} + \sqrt[4]{16} } \\ = \frac{ \sqrt[3]{ {5}^{3} } + \sqrt{ {6}^{2} } }{ \sqrt{ {10}^{2} } + \sqrt[4]{ {2}^{4} } } \\ = \frac{5 + 6}{10 + 2} \\ = \frac{11}{12}$