Question

como factorizo 4n^2+n-33??

Answer 1

$\mathrm{Factorizar}\:4n^2+n-33:\quad \left(4n-11\right)\left(n+3\right)$

Pasos

$4n^2+n-33$

$\mathrm{Factorizar\:la\:expresion}$

$=\left(4n^2-11n\right)+\left(12n-33\right)$

$\mathrm{Factorizar\:}n\mathrm{\:de\:}4n^2-11n\mathrm{:\quad }n\left(4n-11\right)$

$\mathrm{Factorizar\:}3\mathrm{\:de\:}12n-33\mathrm{:\quad }3\left(4n-11\right)$

$=n\left(4n-11\right)+3\left(4n-11\right)$

$\mathrm{Factorizar\:el\:termino\:comun\:}4n-11$

$=\left(4n-11\right)\left(n+3\right)$