Question

Resuelve las siguientes ecuaciones quitando para ello el paréntesis antes:
a) 3(x – 7) = 5(x – 1) – 4
b) 5(2 – x) + 3(x + 6) = 10 – 4(6 + 2x)
c) 3x + 8 – 5x – 5 = 2(x + 6) – 7x
d) 10(x – 2) = 1

Answer 1

Respuesta:

a) 3(x – 7) = 5(x – 1) – 4

3x - 21 = 5x - 5 - 4

3x - 21 = 5x - 9

3x - 5x = -9 + 21

-2x = 12

x = -6

b) 5(2 – x) + 3(x + 6) = 10 – 4(6 + 2x)

10 - 5x + 3x + 18 = 10 - 24 - 8x

-5x + 3x + 18 = -24 -8x

-2x + 18 = -24 - 8x

-2x + 8x = -24 -18

6x = -42

x = 7

c) 3x + 8 – 5x – 5 = 2(x + 6) – 7x

-2x + 3 = 2x + 12 - 7x

-2x + 3 = -5x + 12

-2x + 5x = 12 - 3

3x = 9

x = 3

d) 10(x – 2) = 1

10x - 20 = 1

10 x = 1 + 20

10x = 21

x = 21/10

Espero te sirva c;

uwu coronita plis