Question

Cuanto es 1/2a^2b^3+1/4a^3b^4-1/8a^2b^5+1/16a^4b^2

Answer 1

$\frac{1}{2}a^2b^3+\frac{1}{4}a^3b^4-\frac{1}{8}a^2b^5+\frac{1}{16}a^4b^2=\frac{a^2b^3}{2}+\frac{a^3b^4}{4}-\frac{a^2b^5}{8}+\frac{a^4b^2}{16}$

Pasos

$\frac{1}{2}a^2b^3+\frac{1}{4}a^3b^4-\frac{1}{8}a^2b^5+\frac{1}{16}a^4b^2$

$\frac{1}{2}a^2b^3=\frac{a^2b^3}{2}$

$\frac{1}{4}a^3b^4=\frac{a^3b^4}{4}$

$\frac{1}{8}a^2b^5=\frac{a^2b^5}{8}$

$\frac{1}{16}a^4b^2=\frac{a^4b^2}{16}$

$=\frac{a^2b^3}{2}+\frac{a^3b^4}{4}-\frac{a^2b^5}{8}+\frac{a^4b^2}{16}$