Question

Encontrar la derivada y=(x-1)(x²+x+1)

Answer 1

Respuesta: $3x^2$

Explicación paso a paso:

$(x-1)(x^2+x+1)\\y=xx^2+xx+x\cdot \:1+\left(-1\right)x^2+\left(-1\right)x+\left(-1\right)\cdot \:1\\y=x^3-1\\\\\frac{dy}{dx}=\frac{d}{dx}\left(x^3-1\right)=3x^2$