Question

3(x-1)+5(x-2)-(x-3)=18

2(x-3)-4(x-1)+(x-5)=2x+20

Answer 1

$3(x-1)+5(x-2)-(x-3)=18 \\ \\ 3x-3+5x-10-x+3=18 \qquad aplicamos \ distributiva \\ \\ 3x+5x-x=18+3+10-3 \\ \\ 7x=28\to x= \frac{28}{7}\to \boxed{x= 4}$


$2(x-3)-4(x-1)+(x-5)=2x+20 \\ \\ 2x-6-4x+4+x-5= 2x+20 \\ \\ 2x-4x+x-2x=20+5-4+6 \\ \\ -3x= 27\to x= \frac{27}{-3}\to \boxed{x= -9}$

Espero que te sirva, salu2!!!!

Answer 2

1.
3(x-1)+5(x-2)-(x-3)=18
3x-3+5x-10-x+3=18
7x-10=28
7x=28
x=4

2.
2(x-3)-4(x-1)+(x-5)=2x+20
2x-6-4x+4+x-5=2x+20
-x-7=2x+20
-3x=27
-x=9
x=-9