Question

hallar x en :
$2 {}^{x} \times 2 {}^{3x} \times 2 {}^{5x - 9 } = 32 {}^{x - \frac{2}{5} }$
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Answer 1

Respuesta:

$2 ^{ x} \times 2^{3x} \times 2^{5x - 9} = 32^{x - \frac{2}{5} }$

$2 ^{9x - 9} = 2^{5x - 2}$

$9x - 9 = 5x - 2$

$9x - 5x = 2 + 9$

$4x = 7$

$x = \frac{7}{4} = 1.75$