Question

Calcular1/X^2+X>1/X^2-X

Answer 1

Respuesta:

$x>0$

Explicación paso a paso:

$\frac{1}{x^2}+x>\frac{1}{x^2}-x\\\\\frac{1}{x^2}+x+x>\frac{1}{x^2}-x+x\\\\\frac{1}{x^2}+2x>\frac{1}{x^2}\\\\\frac{1}{x^2}+2x-\frac{1}{x^2}>\frac{1}{x^2}-\frac{1}{x^2}\\\\2x>0\\\\\frac{2x}{2}>\frac{0}{2}\\\\\frac{2x}{2}>0\\\\\frac{2x}{2}\cdot \:2>0\cdot \:2\\\\\frac{2x}{2}>\frac{0}{2}\\\\x>0$

espero que te ayude

#yoaprendi