Question

3- pasar a lenguaje coloquial 3a-1 3(a-1) 4b+1 4(b+1) c÷2-1 (c-1):2 d÷3-1 (d-1)÷3 n^(2)-1 (n-1)^(2) ^(2) es al cuadrado ok :'>?​

Answer 1

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Answer 2

Jensen






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