Question

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Answer 1

Respuesta:

Solución "M":

$\\ \frac{{2}^{12}.3 {}^{11}.2 {}^{15}.3 {}^{10} }{ {2}^{25}.3 {}^{20} } =$

$\\ \frac{2 {}^{12 + 15}.3 {}^{11 + 10} }{2 {}^{25}.3 {}^{20} } =$

$\\ \frac{2 {}^{27}.3 {}^{21} }{2 {}^{25}.3 {}^{20} } =$

$\\ {2}^{27 - 25}. {3}^{21 - 20} = {2}^{2}. {3}^{1} = \\4.3 = 12$

Solución "N":

$\\ \frac{ {3}^{15}. {7}^{9}. {3}^{10}. {7}^{11} }{ {3}^{23}. {7}^{19} } =$

$\\ \frac{ {3}^{15 + 10}. {7}^{9 + 11} }{ {3}^{23}. {7}^{19} } =$

$\\ \frac{ {3}^{25}. {7}^{20} }{ {3}^{23}. {7}^{19} } =$

${3}^{25 - 23}. {7}^{20 - 19} = \\ {3}^{2} . {7}^{1} = 9.7 \\ \: \: \: \: = 63$

Solución " P":

$\\ \frac{ {5}^{18}. {11}^{17}. {5}^{12}. {11}^{9} }{ {5}^{29}. {11}^{25} } =$

$\\ \frac{ {5}^{18 + 12}. {11}^{17 + 9} }{ {5}^{29}. {11}^{25} } =$

$\\ \frac{ {5}^{30}. {11}^{26} }{ {5}^{29}. {11}^{25} } =$

$\\ {5}^{30 - 29}. {11}^{26 - 25} = \\ {5}^{1}. {11}^{1} = \\ 5.11 = 55$

:-) Espero que te ayude!!!