Question

Si: ctga =1/3; donde a: angulo agudo
Calcule: seca. csca​

Answer 1

Respuesta:

Explicación paso a paso:

$CTG a = \frac{1}{3} = \frac{CA}{CO} \\\\H ^{2} = CO^{2} + CA^{2} \\\\ H^{2} = 3^{2} + 1^{2} \\H^{2} = 10\\ H = \sqrt{10} \\\\seca . csca = \frac{H}{CA} . \frac{H}{CO} \\\\\frac{\sqrt{10} }{1 } . \frac{\sqrt{10} }{3 } \\\\\frac{10}{3}$