Question

x^{10}-5x^8+x^6+3x^4-2x^2-1\div \:x^2+1 porfaaaaaaa

Answer 1

Respuesta:

$\begin{lgathered}x^{10}-5x^8+x^6+3x^4-2x^2-1\div \:x^2+1\\\\=x^8+\frac{-6x^8+x^6+3x^4-2x^2-1}{x^2+1}\\\\=x^8-6x^6+\frac{7x^6+3x^4-2x^2-1}{x^2+1}\\\\=x^8-6x^6+7x^4+\frac{-4x^4-2x^2-1}{x^2+1}\\\\=x^8-6x^6+7x^4-4x^2+\frac{2x^2-1}{x^2+1}\\\\=x^8-6x^6+7x^4-4x^2+2+\frac{-3}{x^2+1}\\\\simplificar\\\\=x^8-6x^6+7x^4-4x^2+2-\frac{3}{x^2+1}\end{lgathered}$