Question

hola quien me explica??


$(3 {}^{4} \div 3 {}^{2} + 80 {}^{0} \times 1 {}^{80} ) \div \sqrt[5]{32}$
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Answer 1

Respuesta:

(3/4=3*3*3*3=81)+(3/2=3*3=9)=90+(80/0=80*0=0)90+0=90(1/80=1*1*1*1*...=1)90*1=90

Explicación paso a paso:

lo demas nuse .<.

Answer 2

3^4 = 3x3x3x3 = 81

3^2 = 3x3 = 9

80^0 = 1

1^80 = 1

5√32 = 2 ———> 2x2x2x2x2 = 32

(81 ÷ 9 + 1 x 1) ÷ 2

(9 + 1) ÷ 2

10 ÷ 2

= 5