Question

2. SUMAS Y RESTAS
1)(3x4−2x6+x3−x+5)+(x6−3x2+4x−1)=
2)(2x+3x3−5x3+2x4+5x−1)+(8x3−x4+5x2−9x3)=
3)(2x5−3x4+x3−8x2+2x−7)+(−4+2x2−6x4+x5)=
4)(4x4−3x3+5x4+8x3−4x2+3)−(−5x3−4x4+7+2x2−5x)=
5)(2x7+x5−4x+6x3−2)−(9x3−12x5+2x7−3x3)=

Answer 1

Respuesta:

8x +5

Explicación paso a paso:

1) (3 x 4 -2 x 6 +3x-x +5)+(x6 -3x2 +4x-1)

12-12+2x+5 + 10x - 5

2x + 5 + 10x - 5

8x + 5

Asi que daria