Question

AYUDA!!!! 4X(X+3)+(X+2)(X-2)=(2X+3)`2+X-1=

Answer 1

Respuesta:

$\quad x_{1}=\frac{-7- \sqrt{229}}{10}$

$\quad x_{2}=\frac{-7+ \sqrt{229}}{10}$

Explicación paso a paso:

$4x(x+3)+(x+2)(x-2)=(2x+3)2+x-1$

$4x^{2}+12x+x^{2}-4 =4x+6+x-1$

$5x^{2}+12x-4 =5x+5$

$5x^{2}+7x-9 =0$

Fórmula para ecuaciones de segundo grado:

$ax^2+bx+c=0$

$\quad x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\quad x_{1,\:2}=\frac{-7\pm \sqrt{7^2-4(5)(-9)}}{2(5)}$

$\quad x_{1,\:2}=\frac{-7\pm \sqrt{49+180}}{10}$

$\quad x_{1,\:2}=\frac{-7\pm \sqrt{229}}{10}$

$\quad x_{1}=\frac{-7- \sqrt{229}}{10}$

$\quad x_{2}=\frac{-7+ \sqrt{229}}{10}$