Question

2^2x-12×+32=0 resolver paso a paso

Answer 1

Explicación paso a paso:

$\begin{lgathered}2^2x-12+32=0\\\\2^2x+20=0\\\\4x+20=0\\\\4x+20-20=0-20\\\\4x=-20\\\\\frac{4x}{4}=\frac{-20}{4}\\\\x=-5\end{lgathered}$