Question

Una persona de corazón noble que me pueda ayudar por favor

Answer 1

Respuesta:

Explicación:

1

$\frac{d}{dx}\left(10\right)=0$

2

$\frac{d}{dx}\left(x-1\right)=1$

3

$\frac{d}{dx}\left(-3x+5\right)=-3$

4

$\frac{d}{dx}\left(\pi x\right)=\pi$

5

$\frac{d}{dx}\left(3x^2\right)=6x$

6

$\frac{d}{dx}\left(-x^2+1\right)=-2x$

7

$\frac{d}{dx}\left(-x^2+4x+1\right)=-2x+4$

8

$\frac{d}{dx}\left(\frac{1}{2}x^2+6x-7\right)=x+6$

9

$\frac{d}{dx}\left(\left(x+1\right)^2\right)=2\left(x+1\right)$

10

$\frac{d}{dx}\left(\left(2x-5\right)^2\right)=4\left(2x-5\right)$

11

$\frac{d}{dx}\left(x^3+x\right)=3x^2+1$

12

$\frac{d}{dx}\left(2x^3+x^2\right)=6x^2+2x$

13

$\frac{d}{dx}\left(-x^3+15x^2-x\right)=-3x^2+30x-1$

14

$\frac{d}{dx}\left(3x^4\right)=12x^3$

15

$\frac{d}{dx}\left(\frac{2}{x+1}\right)=-\frac{2}{\left(x+1\right)^2}$

16

$\frac{d}{dx}\left(\frac{x}{x-1}\right)=-\frac{1}{\left(x-1\right)^2}$

17

$\frac{d}{dx}\left(\frac{2x+3}{x+4}\right)=\frac{5}{\left(x+4\right)^2}$

18

$\frac{d}{dx}\left(\frac{1}{x}+\frac{1}{x^2}\right)=-\frac{1}{x^2}-\frac{2}{x^3}$

19

$\frac{d}{dx}\left(\frac{1}{\sqrt{x}}\right)=-\frac{1}{2x^{\frac{3}{2}}}$

20

$\frac{d}{dx}\left(\sqrt{2x+1}\right)=\frac{1}{\sqrt{2x+1}}$