Question

ayudenmen en esto por favor es para mañana ​

Answer 1

Respuesta:

Ahí está la solución

Explicación paso a paso:

Se multiplica aplicando la ley de signos:

$6.- (4a^{2} - 3b^{3})^{2} = (4a^{2} )^{2} - 2(4a)(3b^{3}) +(3b^{3} )^{2} = 16a^{4} -24ab^{3} + 9b^{6}$

$7.- (4ax - 1)^{2} = (4ax)^{2}-2(4ax)(1) +(1)^{2} = 16a^{2}x^{2} -8ax+1$$8.-(2m-3n)^{2}=(2m)^{2}-2(2m)(3n)+(3n)^{2}=4m^{2}-12mn+9n^{2}$$9.-(x^{5}-3ay^{2})^{2}=(x^{5}) ^{2}-2(x^{5})(3ay^{2})+(3ay^{2}) ^{2}=x^{10}-6ax^{5}y^{2}+9a^{2}y^{4}$

$10.- (9-a)^{2}=(9)^{2}-2(9)(a)+(a)^{2}=81-18a+a^{2}$

$16.- (a+1)(a+2)=(a)(a)+(a)(2)+(1)(a)+(1)(2)=a^{2}+2a+a+2=a^{2}+3a+2$

$17.-(x-3)(x-1)=(x)(x)-(x)(1)-(3)(x)+(3)(1)=x^{2} -x-3x+3=x^{2} -4x+3$

$18.-(a^{6}+7)(a^{6}-9)=(a^{6})(a^{6})-(a^{6})(9)+(7)(a^{6})-(7)(9)=a^{12}-9a^{6}+7a^{6}-63=a^{12}-2a^{6}-63$

$19.-(ab+5)(ab-6)=(ab)(ab)-(ab)(6)+(5)(ab)-(5)(6)=a^{2}b^{2}-6ab+5ab-30=a^{2}b^{2}-ab-30$

$20.-(a-3)(a+8)=(a)(a)+(a)(8)-(3)(a)-(3)(8)=a^{2}+8a-3a-24=a^{2}+5a-24$