Question

Perdon por la anterior foto y espero que me puedan ayudar ​

Answer 1

Respuesta:

b. $-\frac{2}{4}+\frac{5}{2} =\frac{-2+10}{4}=\frac{8}{4}=2$

c. $1-\frac{7}{8}=\frac{8-7}{8}=\frac{1}{8}$

d. $-\frac{1}{3}-\frac{1}{4}=\frac{-4-3}{12}=-\frac{7}{12}$

e. $\frac{4}{5}-\frac{5}{3}=\frac{12-25}{15}=-\frac{13}{25}$

f. $-\frac{2}{3}-1=\frac{-2-3}{3}=-\frac{5}{3}$

g. $\frac{1}{4}+\frac{3}{2}+\frac{2}{5}=\frac{5.1+10.3+4.2}{20}= \frac{5+30+8}{20}=\frac{43}{20}$

h. $\frac{3}{5}+\frac{3}{2}+\frac{2}{6}=\frac{6.3+15.3+5.2}{30} =\frac{18+45+10}{30} =\frac{73}{30}$

i. $-\frac{5}{6}+\frac{3}{4}-\frac{2}{3}=\frac{2.-5+3.3+4.-2}{12}=\frac{-10+9-8}{12}=-\frac{9}{12}=-\frac{3}{4}$

j. $-\frac{8}{15}-\frac{1}{3}-\frac{4}{5}=\frac{1.-8+5.-1+3.-4}{15}=\frac{-8-5-12}{15}=-\frac{25}{15}=-\frac{5}{3}$