Question

factorizar 4a²(a² -3) -a²+3 por favor urgente!!!​

Answer 1

Respuesta:

(2a+1)(2a-1)(a²-3)

Explicación paso a paso:

$4a^2\left(a^2-3\right)-a^2+3$

-------------------------------------

$-a^2+3\\=-\left(a^2-3\right)$

-------------------------------------

$=4a^2\left(a^2-3\right)-\left(a^2-3\right)\\=\left(a^2-3\right)\left(4a^2-1\right)$

-------------------------------------

$4a^2-1\\=\left(2a\right)^2-1^2\\=\left(2a+1\right)\left(2a-1\right)$

-------------------------------------

$=\left(2a+1\right)\left(2a-1\right)\left(a^2-3\right)$