Question

Resuelvo las siguientes ecuaciones ayudaaa xfavor

Answer 1

Respuesta:

Explicación paso a paso:

a)

$6x^{2} +7x+2=0\\6x^{2} +4x+3x+2=0\\2x*(3x+2)+3x+2=0\\(3x+2)*(2x+1)=0$

$3x+2=0\\2x+1=0$

$x=-\frac{2}{3} \\2x+1=0$

$x=-\frac{2}{3} \\x=-\frac{1}{2}$

$x_{1} =-\frac{2}{3} , x_{2} =-\frac{1}{2}$

b)$x^{2} -2x-15=0$

$x^{2} +3x-5x-15=0$

$x*(x+3)-5(x+3)=0$

$(x+3)*(x-5)=0$

$x+3=0\\x-5=0$

$x=-3\\x=5$

$x_{1} =-3, x_{2} =5$

c) $2+2x^{2} +5x=0$

$2x^{2} +5x+2=0$

$2x^{2} +4x+x+2=0$

$2x*(x+2)+x+2=0$

$(x+2)*(2x+1)=0$

$x+2=0\\2x+1=0$

$x=-2\\x=-\frac{1}{2}$

$x_{1} =-2, x_{2}=-\frac{1}{2}$

d) $8x^{2} -2x-3=0$

$8x^{2} +4x-6x-3=0$

$4x*(2x+1)-3(2x+1)=0$

$(2x+1)*(4x-3)=0$

$2x+1=0\\4x-3=0$

$x=-\frac{1}{2} \\4x-3=0$

$x=-\frac{1}{2}\\ x=\frac{3}{4}$

$x_{1} =-\frac{1}{2} , x_{2} =\frac{3}{4}$

e) $x^{2} +24=-11x$

$x^{2} +24+11x=0$

$x^{2} +11x+24=0$

$x^{2} +8x+3x+24=0$

$x*(x+8)+3(x+8)=0$

$(x+8)*(x+3)=0$

$x+8=0\\x+3=0$

$x=-8\\x=-3$

$x_{1} =-8, x_{2} =-3$