Question

resolver mediante factorizacion

$-6 x^{2} +103x-17=0$

Answer 1

- 6x² + 103x - 17 = 0

Δ = b² - 4ac
Δ = (103)² - 4 x (- 6) x (- 17)
Δ = 10 609 - 408
Δ = 10 201

x = (- b - √Δ)/2a = (- 103 - 101)/(- 12) = 17
x = (- b + √Δ)/2a = (- 103 + 101)/(- 12) = 1/6