Question

Hallar las siguientes raíces de dos formas: normal y factorización prima ( SI SE PUEDE) escribo los pasos: √279936 √18625 √4096 √256 √100 √4225 √5625 √1024 √3249 √625 √7396 √10000 Porfa ayudenme.

Answer 1

Respuesta:

Explicación paso a paso:

$\sqrt{279936} = 2^{3} * 3^{7} = 216\sqrt{6}$

$\sqrt{18625} = 5^{3} * 149 = 5\sqrt{745}$

$\sqrt{4096} = 64^{2} = \sqrt{64} ^{2} = 64$

$\sqrt{256} = 16^{2} = \sqrt{16} ^{2} = 16$

$\sqrt{100} = 10^{2} = \sqrt{10}^{2} = 10$

$\sqrt{4225}$$= 65^{2} = \sqrt{65}^{2} = 65$

$\sqrt{5625} = 75^{2} =\sqrt{75} ^{2} = 75$

$\sqrt{1024} = 32^{2} = \sqrt{32} ^{2} = 32$

$\sqrt{3249} = 57^{2} =\sqrt{57} ^{2} = 57$

$\sqrt{625} = 25^{2} = \sqrt{25} ^{2} = 25$

$\sqrt{7396} =86^{2} \sqrt{86} ^{2} = 86$

$\sqrt{10000} = 100^{2} = \sqrt{100} ^{2} = 100$