Question

$( \frac{1}{4}m + \frac{1}{2}n)( \frac{1}{4}m - \frac{1}{2}n)$
porfavor ayúdenme ​

Answer 1

Respuesta:

$\frac{3}{16} {m}^{2} n {}^{2}$

Explicación paso a paso:

$( \frac{1}{4}m + \frac{1}{2}n)( \frac{1}{4}m - \frac{1}{2}n) \\ \\ = \frac{1}{16} {m}^{2} - \frac{1}{8} mn + \frac{1}{8} mn - \frac{1}{4} {n}^{2} \\ \\ = \frac{1}{16} {m}^{2} - \frac{1}{4} {n}^{2} \\ \\ = \frac{1 - 4}{16} {m}^{2} n {}^{2} \\ \\ = \frac{3}{16} {m}^{2} n {}^{2}$