Question

Como resolver 2 log 4 (x-3) =1

Answer 1

Respuesta:

la respuesta es  $x=\frac{1}{4\log _{10}\left(2\right)}+3$

Explicación paso a paso:

$2\log _{10}\left(4\right)\left(x-3\right)=1$

$2\log _{10}\left(4\right)$

$=2\cdot \:2\log _{10}\left(2\right)$

$=4\log _{10}\left(2\right)$

$4\log _{10}\left(2\right)\left(x-3\right)=1$

$\frac{4\log _{10}\left(2\right)\left(x-3\right)}{4\log _{10}\left(2\right)}=\frac{1}{4\log _{10}\left(2\right)}$

$x-3=\frac{1}{4\log _{10}\left(2\right)}$

$x-3+3=\frac{1}{4\log _{10}\left(2\right)}+3$

$x=\frac{1}{4\log _{10}\left(2\right)}+3$