Question

ayúdenme por favor es para hoy!! ​

Answer 1

1) Resta -1 a todo:

$\frac{ {x}^{2} + x + 3 }{ {x}^{2} - x + 3 } - 1 = \frac{2x + 5}{2x + 7} - 1 \\ \frac{ {x}^{2} + x + 3 - {x}^{2} + x - 3 }{ {x}^{2} - x + 3} = \frac{2x + 5 - 2x - 7}{2x + 7} \\ \frac{2x}{ {x}^{2} - x + 3 } = \frac{ - 2}{2x + 7} \\ 2x(2x + 7) = - 2( {x}^{2} - x + 3) \\ {4x}^{2} + 14x = { - 2x}^{2} + 2x - 6 \\ {6x}^{2} + 12x + 6 = 0 \\ {x}^{2} + 2x + 1 = 0 \\ {(x + 1)}^{2} = 0 \\ x + 1 = 0 \\ x = - 1$

2)

$\frac{5}{x} - \frac{1}{x + 2} = 1 \\ \frac{5}{x} = \frac{1}{x + 2} + \frac{x + 2}{x + 2} \\ \frac{5}{x} = \frac{x + 3}{x + 2} \\ 5x + 10 = {x}^{2} + 3x \\ {x}^{2} - 2x - 10 = 0 \\ x = \frac{2 \frac{ + }{} \sqrt{44} }{2} \\ x = \frac{2 \frac{ + }{}2 \sqrt{11} }{2} \\ x = 1 + \sqrt{11} \: \: \: o \: \: \: x = 1 - \sqrt{11}$

Answer 2

Respuesta:

Explicación paso a paso: