Question

Si: 2X^2 + 5x + 4 = 0
Halla: G = 4(2x + 1)(x + 1)(2x + 3)(x + 2)​

Answer 1

Respuesta:

Explicación paso a paso:

Si:  

2X^2 + 5x + 4 = 0

Halla:

G = 4(2x + 1)(x + 1)(2x + 3)(x + 2)​

resolución

G = 4 [(2x+1)(x+1)].[(2x+3)(x+2)]

G = 4 [2x²+ x+2x+1].[2x²+3x+4x+6]

G = 4 [2x²+ 3x+1].[2x²+7x+6]

G = 4 [2x²+ 3x+2x-2x+1+3-3].[2x²+7x-2x+2x+6-2+2]

G = 4 [2x²+ (3x+2x)+(1+3)-2x-3].[2x²+(7x-2x)+(6-2)+2x+2]

G = 4 [2x²+ 5x+4 - 2x-3].[2x²+5x+4 +2x+1]

remplazo 2x² + 5x + 4 = 0

G = 4 [0- 2x-3].[0+2x+1]

G = -4 [2x + 3].[2x + 1] = - 4 ( (2x)² + (3+1)(2x) + (3)(1) )

G = - 4(4x²+8x+3)

G = - 16x² - 32x - 12

Answer 2

Respuesta:

Explicación paso a paso:

La respuesta es 8