Question

11a + 22a +33a +44a +....+99a = d(c-4)b3 Hallar : A+B+C+D

Answer 1

Explicación paso a paso:

11a + 22a +33a +44a +....+99a = d(c-4)b3

las últimas cifras

...a + ...a + ...a +...... + ...a = ....3

9×a = ...3

a = ...3/9

a = ...7

a = 7

117 + 227 +337 +447 +....+997 = d(c-4)b3

5013 = d(c-4)b3

d = 5

c = 4

b = 1

a+b+c+d=7+1+4+5=17