Question

logx+log(x+3)=2log(x+1)

Answer 1

logx+log(x+3) = 2log(x+1)        aplicamos propiedad de  logaritmo
log [x * (x + 3)] = log (x + 1)²    ahora podemos cancelar los log!
 [x * (x + 3)] = (x + 1)² 
 [x² + 3 x] = (x² + 2x + 1)
x² + 3x - x² - 2x = 1
3x - 2x =  1
x = 1

espero que te sirva,salu2!!!!