Question

ayudaa porfavorr!! es urgente​

Answer 1

Ejercicio 1:

a)

$\frac{2x+3}{5} \geq 2-\frac{x}{2} \\(2)(2x+3)\geq(5) (4-x)\\4x+6\geq 20-5x\\9x\geq 14\\x\geq \frac{14}{9}$

b)

$\frac{1}{4} (2x-3)+\frac{1}{4} <x-(1-\frac{1}{4} )\\\frac{x}{2} -\frac{3}{4}+\frac{1}{4} <x-\frac{3}{4} \\\frac{-3}{4} +\frac{3}{4} +\frac{1}{4} <x-\frac{x}{2} \\0+\frac{1}{4} < \frac{x}{2} \\\frac{2}{4} <x\\\frac{1}{2} <x\\x>\frac{1}{2}$

Ejercicio 2:

$3x - \frac{1}{2} \leq \frac{x}{4} +1\\3x- \frac{x}{4} \leq 1 + \frac{1}{2} \\ \frac{11x}{4}\leq \frac{3}{2} \\(11)(x)(2)\leq (3)(4)\\22x\leq 12\\x\leq \frac{12}{22} \\x\leq \frac{6}{11}$

Ejercicio 3:

$-nx+\frac{1}{2} <\frac{5}{6}\\ -nx<\frac{5}{6} - \frac{1}{2} \\-nx<\frac{1}{3} \\x<-\frac{1}{3n} \\\\-\frac{1}{9} =-\frac{1}{3n}\\3n=\frac{-9}{-1} \\n=\frac{9}{3} \\n=3$

Ejercicio 4:

a) 5 + ║x-2║ = 3

   ║x-2║= 3 - 5

   ║x-2║= -2

No tiene solución:

x = { }

b) 3║x/2 - 1║ -1 = 8

3║x/2 - 1║ = 9

║x/2 - 1║ = 9/3

║x/2 - 1║ = 3

Solución 1

x/2 -1 = 3

x/2 = 4

x = 8

Solución 2

x/2 -1 = -3

x/2 = -2

x = -4

x = {8 ; -4}