Question

8x−5(4x+1)≥−1+2(4x−3) b) 23x−12(4x−1)≥x+2(x−3) por favor ayudenme

Answer 1

LETRA A

$8x-5\left(4x+1\right)\ge \:-1+2\left(4x-3\right)\\\\-12x-5\ge \:-1+2\left(4x-3\right)\\\\-12x-5\ge \:8x-7\\\\-12x-5+5\ge \:8x-7+5\\\\-12x\ge \:8x-2\\\\-20x\ge \:-2\\\\\mathrm{Multiplicar\:ambos\:lados\:por\:-1\:\left(invierte\:la\:desigualdad\right)}\\\left(-20x\right)\left(-1\right)\le \left(-2\right)\left(-1\right)\\\\20x\le \:2\\\\x\le \frac{1}{10}$

LETRA B

$23x-12\left(4x-1\right)\ge \:x+2\left(x-3\right)\\\\-25x+12\ge \:x+2\left(x-3\right)\\\\-25x+12\ge \:x+2x-6\\\\-25x+12\ge \:3x-6\\\\-25x\ge \:3x-18\\\\-28x\ge \:-18\\\\\mathrm{Multiplicar\:ambos\:lados\:por\:-1\:\left(invierte\:la\:desigualdad\right)}\\\left(-28x\right)\left(-1\right)\le \left(-18\right)\left(-1\right)\\\\28x\le \:18\\x\le \frac{9}{14}$

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