Question

un factor primo de P(x;y)=(x²+x)²+x²+x-6​

Answer 1

Respuesta:

P(x;y)=(x²+x)²+x²+x-6​

x²+x=a

P(x;y)=(a)²+a-6​

P(x;y)=(a-2)(a+3)

P(x;y)=(x²+x-2)(x²+x+3)

P(x;y)=(x+2)(x-1)(x²+x+3)