Question

(x-3)^2+x^2-(x-1)^2=2 con resolución

Answer 1

si:

$(x-3)^{2} + x^2-(x-1)^2=2\\x^2-6x+9+x^2-(x^2-2x+1)=2\\2x^2-6x+9-x^2+2x-1=2\\x^2-4x+8=2\\x^2-4x=-6\\x^2-4x+6=0$