Question

a- 2. √81 - 4²√81 - 4² b-25. √100 √100 +3. 4² 4² c-(50.3-6²6²:12)° d-(2⁵2⁵+√36√36) . √2²+72:6 √2²+72:6 e-(∛1 + 1³)³ (∛1 + 1³)³

Answer 1

Respuesta:

$32a-2\sqrt{81} -4^{2} \sqrt{81} 4^{2} a =178\\b-25.\sqrt{100} \sqrt{100} +3.4^{2} 4^{2} =b-2315.04\\c-(50.3-6^{2} 6^{2} :12)= c -50.3+6^{2} .6^{2} :12\\ d-(2 {^{5} 2^{5} +\sqrt{36}\sqrt{36)}.\sqrt{2^{2} } +76:6\sqrt{2^{2} } +72:6= d-\frac{152639}{72} \\\\\\\\e-(\sqrt[3]{1} +1^{3} )^{3} (\sqrt[3]{1} +1^{3} )^{3} =e- 64$

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