Question

reducir s=(x+4)(x+2)-(x+1)(x+5)

Answer 1

Explicación paso a paso:

primero sama de binomios

(x^2+6x+8) - (x^2+5x+5)

x^2+6x+8-x^2-5x-5

x+3

Answer 2

Respuesta:

S=3

Explicación paso a paso:

$S=\left(x+4\right)\left(x+2\right)-\left(x+1\right)\left(x+5\right)$

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$\left(x+4\right)\left(x+2\right)\\=x^2+6x+8$

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$S=x^2+6x+8-\left(x+1\right)\left(x+5\right)$

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$\left(x+1\right)\left(x+5\right)\\=-\left(x^2+6x+5\right)\\=-x^2-6x-5$

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$=x^2+6x+8-x^2-6x-5\\=x^2-x^2+6x-6x+8-5\\=6x-6x+8-5\\=8-5\\S=3$