Question

(⅕x+3y-2z)-(⅗x-2y) porfa

Answer 1

Respuesta:      $-\frac{2x}{5}+5y-2z$

Pasos:

$\left(\frac{1}{5}x+3y-2z\right)-\left(\frac{3}{5}x-2y\right)$

$\mathrm{Quitar\:los\:parentesis}:\quad \left(a\right)=a$

$=\frac{1}{5}x+3y-2z-\left(\frac{3}{5}x-2y\right)$

$\frac{1}{5}x=\frac{x}{5}$

$-\left(\frac{3}{5}x-2y\right)=-\left(\frac{3x}{5}-2y\right)$

$=\frac{x}{5}+3y-2z-\left(\frac{3x}{5}-2y\right)$

$-\left(\frac{3x}{5}-2y\right):\quad -\frac{3x}{5}+2y$

$=\frac{x}{5}+3y-2z-\frac{3x}{5}+2y$

$\mathrm{Simplificar}\:\frac{x}{5}+3y-2z-\frac{3x}{5}+2y:\quad -\frac{2x}{5}+5y-2z$

$=-\frac{2x}{5}+5y-2z$