Question

64b⁶+1porfavor ayudan rapido

Answer 1

Respuesta:

(4b²+1)(16b⁴-4b²+1)

Explicación paso a paso:

Propiedad distributiva:

A(B+C)=AB+AC

$\displaystyle \mathsf{64b^6+1= \left(4b^2\right)^3+1^3}\\\\\\\displaystyle \mathsf{\left(4b^2\right)^3+1^3}$

Fórmula de suma de cubos:

$\displaystyle \mathsf{X^3+Y^3=\left(X+Y\right)\left(X^2-XY+Y^2\right)}\\\\\\\displaystyle \mathsf{\left(4b^2\right)^3+1^3=\left(4b^2+1\right)\left(4^2b^4-4b^2+1\right)}\\\\\\\textbf{Resolver.}\\\\\\\displaystyle \mathsf{\left(4b^2+1\right)\left(4^2b^4-4b^2+1\right)}\\\\\\\Rightarrow \Large\boxed{\mathsf{\left(4b^2+1\right)\left(16b^4-4b^2+1\right)}}$

Más información sobre el factor: https://brainly.lat/tarea/6270773