Question

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Sistema de Ecuaciones lineales
8s-3t=-3
5s-2t=-1

Answer 1

A) 8s-3t=-3

B) 5s-2t=-1

A) 8s - 3t = -3

-3t = -8s - 3

T = 8/3s + 1

B) 5s - 2t = -1

-2t = -5s - 1

T = 5/2s + 1/2

Igualó las T:

8/3s + 1 = 5/2s + 1/2

8/3s - 5/2s = 1/2 - 1

1/6s = -1/2

s = -1/2 : (1/6)

S = -3

Reemplazo y hallo T

T = 8/3s + 1

T = 8/3 (-3) + 1

T = -8 + 1

T = -7

Solucion: (s,t) =(-3, -7)