Question

resuelve la siguientes ecuaciones 2^x=32

Answer 1

1) $2^{x} = 32$

2 x 2 x 2 x 2 x 2 = 32

=> $2^{5}$

2) $(\frac{1}{2})^{x} = 4$

- Convertimos 4 a base 2:

$(\frac{1}{2})^{x} = 2^{2}$

- Convertir $\frac{1}{2}$ a base 2:

$2^{-x} = 2^{2}$

:. -x = 2 o x = -2

=> $(\frac{1}{2})^{-2} = 4$

3) $4^{-x} = 64$

- Convertimos 64 a base 4

$4^{-x} = 4^{3}$

:. -x = 3

=> $4^{3} = 64$