Question

porfavor ayuda con esto ,resolver con proceso
a.(2^4 × 2^3 × 2^3)/(2^(3 )× 2^5 )=
b.[(-2)^2 ]^4
c.(5^(6 )× 5^4 )÷ 5^7

Answer 1

Respuesta:

Explicación paso a paso:

a.(2^4 × 2^3 × 2^3)/(2^(3 )× 2^5 )=

= 16(2^3)(2^3) /(2^3)(2^5)

= (16)(8)(2^3) /(2^3)(2^5)

= 128(2^3) /(2^3)(2^5)

= (128)(8) /(2^3)(2^5)

= 1024 /(2^3)(2^5)

= 1024 /8(2^5)

= 1024 /(8)(32)

= 1024 /256

b.[(-2)^2 ]^4

2))*((−2)*=((−2)^2)^4

=((−2)^2)*((−2)^2)*((−2)^2)*((−2)^2)

=((−2)*(−(−2))*((−2)*(−2))*((−2)*(−2))

=(−2)*(−2)*(−2)*(−2)*(−2)*(−2)*(−2)*(−2)

=(−2)^ 8

=256

c.(5^(6 )× 5^4 )÷ 5^7

= 15625(5^4) /5^7

= (15625)(625) /5^7

= 9765625 /5^7

= 9765625 /78125

=125