Question

Si senx=2/5 y tany=4/3
M=cscx/coty

Answer 1

$\texbf{Si:}\\\mathbf{\sin(x)=2/5\,\,,\tan(x)=4/3}$

Recordemos

$\csc(x)=\frac{1}{\sin(x)}\\\\\cot(x)=\frac{\cos(x)}{\sin(x)}=\frac{1}{\tan(x)}$

Aplicando lo anterior nos queda:

$M=\frac{\csc(x)}{\tan(x)}=\frac{\frac{1}{2/5}}{\frac{1}{4/3}}=\frac{4/3}{2/5}=\frac{20}{6}=\frac{10}{3}$

Saludos