Question

sacar x de (3^3x)(27)=(9^5x-7)(3^2x-1)​

Answer 1

Respuesta:

$(3^3x)(27)=(9^5x-7)(3^2x-1)​$

$27x27=729=59.049‬-7=59.042‬=9x1-1=59.041$

RESPUESTA= 59.041