Question

1/cos(x)-cos(x)/1+sin(x)=tan(x)

Answer 1

Respuesta:

Explicación paso a paso:

$\frac{1}{cosx} -\frac{cosx}{1+senx} =tanx\\\\\frac{1+senx-cosx^{2} }{cosx(1+senx)} =tanx\\\\\frac{1+senx-(1-senx^{2} }{cosx(1+senx)} =tanx\\\\\frac{senx+senx^{2} }{cosx(1+senx)} =tanx\\\\\frac{senx(1+senx)}{cosx(1+senx)} =tanx\\\\\\\frac{senx}{cosx} =tanx\\tanx=tanx$