Question

Si: a1 = 1 ; a2 = 2 y an = 3an-1 – 2an-2 ; n > 3 Determina: a40 = ?

Answer 1

Respuesta:

Explicación paso a paso:

$a_{n}=3a_{n-1}-2a_{n-2}\\a_{3}=3a_{2}-2a_{1}\\a_{3}=3.2-2.1\\a_{3}=4\\a_{4}=3a_{3}-2a_{2}\\a_{4}=3.4-2.2\\a_{4}=8\\\\a_{5}=3a_{4}-2x^{2} a_{3}\\a_{5}=3.8-2.4\\a_{5}=16\\\\2^{0}, 2^{1},2^{2},2^{3},2^{4}...........................2^{39}\\a_{40}=2^{39}$