Question

Buen día, me ayudan con productos notables.
1) (2/3m⁴ - 1)²
2) (0, 5a² - 1,2b³)²
3) (3√ 2x - 3)²

Answer 1

Respuesta:

Explicación paso a paso:

Recordemos:

$(a-b)^{2}=(a)^{2}-2(a)(b)+(b)^{2}=a^{2}-2ab+b^{2}$

Aplicando lo anterior a cada $\textbf{producto notable}$ nos queda:

$(2/3m^{4}-1)^{2}=(2/3m^{4})^{2}-2(2/3m^{4})(1)+(1)^{2}=4/9m^{8}-4/3m^{4}+1$

$(0.5a^{2}-1.2b^{3})^{2}=(0.5a^{2})^{2}-2(0.5a^{2})(1.2b^{3})+(1.2b^{3})^{2}=0.25a^{4}-1.2a^{2}b^{3}+1.44b^{6}$

$(3\sqrt{2}x-3)^{2}=(3\sqrt{2}x)^{2}-2(3\sqrt{2}x)(3)+(3)^{2}=(3\sqrt{2})^{2}(x)^{2}-2(3\sqrt{2}x)(3)+(3)^{2}=18x^{2}-18\sqrt{2}x+9$

Saludos